SOLUTION: use log(4, 7)=1.4037 and log(4, 3)= 0.7925 to evaluate each expression log(4, 9) log(4, 7/12)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: use log(4, 7)=1.4037 and log(4, 3)= 0.7925 to evaluate each expression log(4, 9) log(4, 7/12)      Log On


   

Question 459265: use log(4, 7)=1.4037 and log(4, 3)= 0.7925 to evaluate each expression
log(4, 9)
log(4, 7/12)
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
use log(4, 7)=1.4037 and log(4, 3)= 0.7925 to evaluate each expression
log(4, 9)
we can rewrite the 9 as 3^2
log(4, 3^2)
2*log(4, 3)
now we can perform the substitution:
2*0.7925
1.585

.
log(4, 7/12)
we rewrite as:
log(4, 7) - log(4,12)
log(4, 7) - [log(4,4*3)]
log(4, 7) - [log(4,4) + log(4,3)]
log(4, 7) - [log(4,4) + log(4,3)]
1.4037 - [1 + 0.7925]
1.4037 - 1.7925
-0.3888