SOLUTION: Louis lives 5 miles from school and jogs at a rate of 6 mph. Andrea lives 3.9 miles from school and jogs at a rate of 6.5 mph. Andrea leaves her house at 7am. When should Louis
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Question 459004: Louis lives 5 miles from school and jogs at a rate of 6 mph. Andrea lives 3.9 miles from school and jogs at a rate of 6.5 mph. Andrea leaves her house at 7am. When should Louis leave his house to arrive at school at the same time as Andrea? Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! 3.9 miles/6.5 mph=.6 hours
5 miles/6 mph=.83 hours=50 mins
Andrea arrives at school at 7:36 (7 a.m. + .6 hours), So Louis should leave 50 minutes before then, or at 6:46 a.m..
