SOLUTION: I NEED HELP WITH MY MATH PROBLEM. BASICALLY THERE IS A BAG FULL OF MARBLES AND THERE ARE 3 DIFFERENT COLORS OF MARBLES RED, YELLOW AND BLUE. WE HAVE TO FIGURE OUT THE TOTAL AMOUNT

Algebra ->  Probability-and-statistics -> SOLUTION: I NEED HELP WITH MY MATH PROBLEM. BASICALLY THERE IS A BAG FULL OF MARBLES AND THERE ARE 3 DIFFERENT COLORS OF MARBLES RED, YELLOW AND BLUE. WE HAVE TO FIGURE OUT THE TOTAL AMOUNT       Log On


   

Question 458815: I NEED HELP WITH MY MATH PROBLEM. BASICALLY THERE IS A BAG FULL OF MARBLES AND THERE ARE 3 DIFFERENT COLORS OF MARBLES RED, YELLOW AND BLUE. WE HAVE TO FIGURE OUT THE TOTAL AMOUNT OF MARBLES IN BAG AND HOW MANY MARBLES ARE THERE FOR EACH COLOR. THE ODDS AGAINST GETTING RED IS 6:5 AND ODDS AGAINST GETTING BLUE IS 3:7 AND ODDS AGAINST GETTING RED IS X:10. THANKS FOR HELPING AND PLEASE SHOW ALL YOUR STEPS.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
THERE IS A BAG FULL OF MARBLES AND THERE ARE 3 DIFFERENT COLORS OF MARBLES RED, YELLOW AND BLUE. WE HAVE TO FIGURE OUT THE TOTAL AMOUNT OF MARBLES IN BAG AND HOW MANY MARBLES ARE THERE FOR EACH COLOR.
THE ODDS AGAINST GETTING RED IS 6:5
AND ODDS AGAINST GETTING BLUE IS 3:7
AND ODDS AGAINST GETTING YELLOW IS X:10.
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Probability of red is 5/11
Probability of blue is 7/10
Probability of yellow is 10/(x+10)
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Equation:
(5/11) + (7/10) + 10/(x+10) = 1
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Multiply thru by 11*10*(x+10) to get:
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5*10(x+10) + 7*11(x+10) + 10*11*10 = 11*10*(x+10)
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50(x+10) + 77(x+10) + 10*11*10 = 110(x+10)
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17(x+10) = 1100
x+10 = 64.7
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Note: That should turn out to be a whole number.
Please check your problem statement and my arithmetic.
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Cheers,
Stan H.