SOLUTION: David got in his '29 Ford and started driving west from Florida at a constant speed of 30 miles per hour. An hour later Anna got in her '31 Buick and started driving west from Flor

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Question 458690: David got in his '29 Ford and started driving west from Florida at a constant speed of 30 miles per hour. An hour later Anna got in her '31 Buick and started driving west from Florida at a constant speed. After driving 4 hours Anna had passed David and was 10 miles ahead of him. How fast was Anna driving?
PLEASE ANSWER MY QUESTION!!!!! PLEASE!!!
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Found 3 solutions by stanbon, mananth, richwmiller:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website!
David got in his '29 Ford and started driving west from Florida at a constant speed of 30 miles per hour. An hour later Anna got in her '31 Buick and started driving west from Florida at a constant speed. After driving 4 hours Anna had passed David and was 10 miles ahead of him. How fast was Anna driving?
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David DATA:
rate = 30 mph ; time = 5 hrs ; distance = rt = 30*5 = 150 miles
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Anna DATA:
distance = 160 miles ; time = 4 hrs ; rate = d/t = 160/4 = 40 mph
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Anna's rate = 40 mph
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Cheers,
Stan H.
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Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website!
David speed = 30 mph
Anna speed = x mph
Anna leaves after 1 hour
In 1 hour David has traveled 30 miles
So catch up distance = 30 miles.
Anna is 10 miles ahead of David after 4 hours
30+10 = 40 miles
catch up time = 4 hours
catch up speed = x-30
r=d/t
x-30=40/4
4(x-30)= 40
4x-120=40
4x=120+40
4x=160
x=40 mph speed of Anna

Answer by richwmiller(17219)   (Show Source):
You can put this solution on YOUR website!
4x=30*5+10
4x=160
x=40 mph