SOLUTION: hi im not really sure if my question would be in this category but if you could help me the best way you can that would mean a lot to me thanks
[3x-2/2x^2-5x-3]-[1/x-3]
can
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: hi im not really sure if my question would be in this category but if you could help me the best way you can that would mean a lot to me thanks
[3x-2/2x^2-5x-3]-[1/x-3]
can
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Question 458657: hi im not really sure if my question would be in this category but if you could help me the best way you can that would mean a lot to me thanks
[3x-2/2x^2-5x-3]-[1/x-3]
can you please walk me through this im clueless Answer by stanbon(75887) (Show Source):
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Factor where you can:
= [3x-2/(x-3)(2x+1)]-[1/x-3]
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Least common denominator: (x-3)(2x+1)
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Rewrite each fraction with the lcd as its denominator:
= [(3x-2)/lcd] - [(2x+1)/lcd]
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Combine the numerators over the lcd:
= [3x-2-2x-1]/lcd
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= (x-3)/[(x-3)(2x+1)]
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Cancel the common (x-3) factor to get:
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= 1/(2x+1)
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Cheers,
Stan H.
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