You can put this solution on YOUR website! Find the value of z such that approximately 30.78% of the distribution lies between it and the mean.
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0.50-.3078 = 0.1922
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Find the z-value with a left tail of 0.1922
invNorm(0.1922) = -0.8698
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The answer could also be +0.8698
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Cheers,
Stan H.
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