SOLUTION: For z always positive, what does x equal in the equation
z = x^(x^(y-1))?
I submitted this several times, one answer was
z=x^(x^(y-1))
x^x = z^(1/(y-1))
x = z^(1/x(y-1))
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: For z always positive, what does x equal in the equation
z = x^(x^(y-1))?
I submitted this several times, one answer was
z=x^(x^(y-1))
x^x = z^(1/(y-1))
x = z^(1/x(y-1))
Log On
Question 458458: For z always positive, what does x equal in the equation
z = x^(x^(y-1))?
I submitted this several times, one answer was
z=x^(x^(y-1))
x^x = z^(1/(y-1))
x = z^(1/x(y-1))
This doesn't work out with actual numbers. For example:
z=19683, x=3, y=3. 19683 = 3^(3^(3-1)). Works fine.
But:
x^x = z^(1/(y-1)) is not true because
3^3 doesn't equal 19683^(1/(3-1))
27 doesn't equal 140.2961154. Is there something I'm missing here? Am I
reading the above answer incorrectly? Answer by richwmiller(17219) (Show Source):
