SOLUTION: How much of a 80% alcohol solution must be mixed with 40 gallons of a 14% alcohol solution to obtain a solution of 70% alcohol?

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Question 458318: How much of a 80% alcohol solution must be mixed with 40 gallons of a 14% alcohol solution to obtain a solution of 70% alcohol?
Answer by Alan3354(69443) About Me  (Show Source):
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How much of a 80% alcohol solution must be mixed with 40 gallons of a 14% alcohol solution to obtain a solution of 70% alcohol?
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0.8*x + 0.14*40 = 0.7*(x + 14)
Solve for x