SOLUTION: Using the Product rule, h'(x)=f'(x)g(x)+f(x)g'(x), find h'(x) where y=(x+3)^3 x √(2x^2 +1) Thanks.

Algebra ->  Test -> SOLUTION: Using the Product rule, h'(x)=f'(x)g(x)+f(x)g'(x), find h'(x) where y=(x+3)^3 x √(2x^2 +1) Thanks.      Log On


   

Question 458079: Using the Product rule, h'(x)=f'(x)g(x)+f(x)g'(x), find h'(x) where y=(x+3)^3 x √(2x^2 +1)
Thanks.
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Not sure whether you intend for the x between (x+3)^3 and sqrt(2x^2+1) to be a factor of the independent variable or a "times" sign.


John

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