SOLUTION: What conic is described by the equation 8x^2 +8y^2 - 4x + y = 0. Please show steps. Thank you.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: What conic is described by the equation 8x^2 +8y^2 - 4x + y = 0. Please show steps. Thank you.      Log On


   

Question 457506: What conic is described by the equation 8x^2 +8y^2 - 4x + y = 0.
Please show steps. Thank you.
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
What conic is described by the equation 8x^2 +8y^2 - 4x + y = 0.
Please show steps.
..
8x^2 +8y^2 - 4x + y = 0
completing the squares
8(x^2-x/2+1/16)+8(y^2+y/8+1/256)=1/2+1/32=16/32+1/32=17/32
8(x-1/4)^2+8(y+1/16)^2=17/32
divide both sides by 8
(x-1/4)^2+(y+1/16)^2=17/256
This equation is a circle with center at (1/4,-1/16) and radius=sqrt(17/256)=.2577