SOLUTION: A merchant mixed 12 lb of a cinnamon tea with 6 lb of spice tea. The 18-pound mixture cost $39. A second mixture included 14 lb of the cinnamon tea and 10 lb of the spice tea. The
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-> SOLUTION: A merchant mixed 12 lb of a cinnamon tea with 6 lb of spice tea. The 18-pound mixture cost $39. A second mixture included 14 lb of the cinnamon tea and 10 lb of the spice tea. The
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Question 457454: A merchant mixed 12 lb of a cinnamon tea with 6 lb of spice tea. The 18-pound mixture cost $39. A second mixture included 14 lb of the cinnamon tea and 10 lb of the spice tea. The 24-pound mixture cost $53. Find the cost per pound of the cinnamon tea and of the spice tea. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A merchant mixed 12 lb of a cinnamon tea with 6 lb of spice tea.
The 18-pound mixture cost $39.
A second mixture included 14 lb of the cinnamon tea and 10 lb of the spice tea. The 24-pound mixture cost $53.
Find the cost per pound of the cinnamon tea and of the spice tea.
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Equations:
12c + 6t = 39
14c + 10t = 53
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Modify:
4c + 2t = 13
14c + 10t = 53
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Multiply thru 1st eq. by 5:
20c + 10t = 65
14c + 10t = 53
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Subtract and solve for "c":
6c = 12
c = $2.00 per pound (Price of cinnamon tea)
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Solve for "t":
4c + 2t = 13
4*2 + 2t = 13
2t = 5
t = $2.50 per pound (Price of spice tea)
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Cheers,
Stan H.
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