SOLUTION: Answer to each of the following: #1: 8(k+3)=5(k-3) solve for k #2: 6(k-3)=5(-3k-2) solve for k #3: 7+z+2z+7+1-z solve please show me how you solve the above. Thanks!

Algebra ->  Average -> SOLUTION: Answer to each of the following: #1: 8(k+3)=5(k-3) solve for k #2: 6(k-3)=5(-3k-2) solve for k #3: 7+z+2z+7+1-z solve please show me how you solve the above. Thanks!      Log On


   

Question 457379: Answer to each of the following:
#1: 8(k+3)=5(k-3) solve for k
#2: 6(k-3)=5(-3k-2) solve for k
#3: 7+z+2z+7+1-z solve
please show me how you solve the above.
Thanks!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
# 1

8%28k%2B3%29=5%28k-3%29 Start with the given equation.


8k%2B24=5k-15 Distribute.


8k=5k-15-24 Subtract 24 from both sides.


8k-5k=-15-24 Subtract 5k from both sides.


3k=-15-24 Combine like terms on the left side.


3k=-39 Combine like terms on the right side.


k=%28-39%29%2F%283%29 Divide both sides by 3 to isolate k.


k=-13 Reduce.


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Answer:

So the solution is k=-13


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# 2


6%28k-3%29=5%28-3k-2%29 Start with the given equation.


6k-18=-15k-10 Distribute.


6k=-15k-10%2B18 Add 18 to both sides.


6k%2B15k=-10%2B18 Add 15k to both sides.


21k=-10%2B18 Combine like terms on the left side.


21k=8 Combine like terms on the right side.


k=%288%29%2F%2821%29 Divide both sides by 21 to isolate k.


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Answer:

So the solution is k=8%2F21

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# 3

You're missing an equals sign here.