Question 457256: A launched rocket has an altitude, in meters,given by the polynomisl h+vt-4.9t^2, where h is the height, in meters, from which the launch occurs, at velocity v in meters per second, and t is the number of seconds for which the rocket is airborne. if a rocket is launched from the top of a tower 60 meters high with an intial upward of 60 meters per second, what will its height be after 2 seconds?
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! A launched rocket has an altitude, in meters,given by the polynomisl h+vt-4.9t^2, where h is the height, in meters, from which the launch occurs, at velocity v in meters per second, and t is the number of seconds for which the rocket is airborne. if a rocket is launched from the top of a tower 60 meters high with an intial upward of 60 meters per second, what will its height be after 2 seconds?
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Your equation:
h(t) = 60+60t-4.9t^2
at t=2 seconds
h(2) = 60+60(2)-4.9(2)^2
h(2) = 60+120-4.9(4)
h(2) = 60+120-19.6
h(2) = 160.4 meters
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