SOLUTION: FATHER'S AGE IS THRICE THE AGE OF HIS SON,FATHER'S AGE WAS 42 YRS.WHEN SON WAS BORN ,FIND THE FATHER'S AND SON'S AGE WHEN FATHER'S AGE WILL BE 7 TIMES OF THE SON'S AGE.
Question 457255: FATHER'S AGE IS THRICE THE AGE OF HIS SON,FATHER'S AGE WAS 42 YRS.WHEN SON WAS BORN ,FIND THE FATHER'S AND SON'S AGE WHEN FATHER'S AGE WILL BE 7 TIMES OF THE SON'S AGE. Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! The key to this is that the difference in their
ages will always be the same
Let = Father's age now
Let = Son's age now
Let = years from now when Father's age
will be 7 times on's age
given:
(1)
(2)
The difference in their ages will still be
when
(3)
----------------------------------
Substitute (1) into (2)
(2) 3s - s = 42 }}}
and
(1)
and
(3)
(3)
(3)
(3)
(3)
and
When the Father was 49 and the Son was 7,
The Father's age was 7 times the Son's age
