SOLUTION: A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 16 square feet, find the lengths of the sides of the poste

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Question 457134: A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 16 square feet, find the lengths of the sides of the poster and the sign.
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
x2=(x-2)2+16
x2=x2-4x+4+16
4x=20
x=5
The square sign is 5' by 5'. The poster is 3' by 3'..