SOLUTION: If anyone can show the steps taken to complete this problem it would begreatly appreciated. I have been out of school for quite awhile and am still drawing a blank. (x-3)(2x-7)=0

Algebra ->  Human-and-algebraic-language -> SOLUTION: If anyone can show the steps taken to complete this problem it would begreatly appreciated. I have been out of school for quite awhile and am still drawing a blank. (x-3)(2x-7)=0      Log On


   



Question 457079: If anyone can show the steps taken to complete this problem it would begreatly appreciated. I have been out of school for quite awhile and am still drawing a blank. (x-3)(2x-7)=0
Found 2 solutions by Alan3354, MathLover1:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
(x-3)(2x-7)=0
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If the product is zero, one of the factors must be zero.
You can't multiply 2 things and get zero otherwise.
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Either x - 3 = 0 --> x = 3
or
2x - 7 = 0 --> x = 7/2
2 answers: x = 3, x = 7/2

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
%28x-3%29%282x-7%29=0...here you have a quadratic equation already factored; so the roots will be:
if x-3=0...->...x=3
and
if 2x-7=0...->...2x=7...->...x=7%2F2=3.5
let's see it on a graph:
%28x-3%29%282x-7%29=0
2x%5E2-7x-6x%2B21=0
2x%5E2-13x%2B21=0

+graph%28+500%2C+500%2C+-30%2C+15%2C+-15%2C+30%2C+2x%5E2-13x%2B21%29+