SOLUTION: 1) solve: abs(2y+4)=22-abs(6-2y) 2) solve: abs(x-1)-abs(x+2)<abs(x+1)

Algebra ->  Absolute-value -> SOLUTION: 1) solve: abs(2y+4)=22-abs(6-2y) 2) solve: abs(x-1)-abs(x+2)<abs(x+1)      Log On


   



Question 457034: 1) solve: abs(2y+4)=22-abs(6-2y)

2) solve: abs(x-1)-abs(x+2)

Answer by lwsshak3(11628) About Me  (Show Source):
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1) solve: abs(2y+4)=22-abs(6-2y)
2) solve: abs(x-1)-abs(x+2)
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1)abs(2y+4)=22-abs(6-2y)
|2y+4|=22-|6-2y|
let (2y+4)<0
-2y-4=22-6+2y
-4y=22-6+4=20
y=-5
..
|6-2y|=22-|2y+4|
let (6-2y)<0
-6+2y=22-2y-4
4y=22-4+6=24
y=6
..
2) solve: abs(x-1)-abs(x+2
y=|x-1|-|x+2|
for x<-2
y=-x+1-(-x-2)
y=-x+1+x+2=3
..
or x>1
y=x-1-x-2
y=-3
..
for -2 ≤ x ≤1
y=-x+1-(x+2)
y=-x+1-x-2
y=-2x-1