SOLUTION: five years ago a man was seven times as old as his son. five years hence, the father will be three times as old as his son. find their present ages.
Question 456992: five years ago a man was seven times as old as his son. five years hence, the father will be three times as old as his son. find their present ages. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! five years ago a man was seven times as old as his son. five years hence, the father will be three times as old as his son. find their present ages.
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let x=son's current age
5 years ago
son's age=x-5
father's age = 7(x-5)
5 years hence
son's age=x+5
father's age=7(x-5)+10
7(x-5)+10=3(x+5)
7x-35+10=3x+15
4x=40
x=10
7(x-5)+5=35
ans:
son's current age=10
father's current age=35
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