Question 456944: Draw the parabola. Identify the focus and directrix and show them on the graph.
x+1/4y^2=0
Also find the
focus:
Directrix: Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Draw the parabola. Identify the focus and directrix and show them on the graph.
x+1/4y^2=0
Also find the
focus:
Directrix:
..
x+1/4y^2=0
y^2/4=-x
y^2=-4x
..
Standard form for parabola: (y-k)^2=4p(x-h), with (h,k) being the (x,y) coordinates of the vertex.
For given parabola:
vertex at (0,0)
Axis of symmetry, y=0 or x-axis
Parabola opens leftward
4p=4
p=1
focus, (-1,0)
directrix, x=1
see following graph as a visual check on the answers.
..
y=(-4x)^.5
(