SOLUTION: Solve: logbase3(logbasex(logbase4 16)) = 1
Solve: 6^2logbase6 X + logbase6 X =125
Write the expression as a single logarithm:
3loga - logb - (1/2)logc
Question 456781: Solve: logbase3(logbasex(logbase4 16)) = 1
Solve: 6^2logbase6 X + logbase6 X =125
Write the expression as a single logarithm:
3loga - logb - (1/2)logc Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Solve: logbase3(logbasex(logbase4 16)) = 1
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log3(logx(2)) = 1
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logx(2) = 3
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x^3 = 2
x = 2^(1/3)
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Solve: 6^2logbase6 X + logbase6 X =125
36*log6(x)) + log6(x) = 125
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37log6(x) = 125
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x^37 = 6^125
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x = 425.49
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Write the expression as a single logarithm:
3loga - logb - (1/2)logc
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loga^3 - logb - logc^(1/2)
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= log[a^3/(bc^(1/2))]
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Cheers,
Stan H.
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