Question 456397: The sum of the squares of two consecutive positive odd integers is 202. Find the numbers. Found 2 solutions by tinbar, Alan3354:Answer by tinbar(133) (Show Source):
You can put this solution on YOUR website! if we have some number x, then it's consecutive will be x+1
so in math language, the question asks you to solve (x)^2 + (x+1)^2 = 202
2x^2+2x+1=202
2x^2+2x-201 = 0
use the quadratic formula and solve for x!
You can put this solution on YOUR website! The sum of the squares of two consecutive positive odd integers is 202. Find the numbers.
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202/2 = 101
sqrt(101) = about 10, the center
--> 9 & 11
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