SOLUTION: Find three consecutive integers such that the sum of twice the first and 4 times the second is equal to 20 more than twice the third.

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Question 456387: Find three consecutive integers such that the sum of twice the first and 4 times the second is equal to 20 more than twice the third.
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
Let x, x+1 & x+2 be the three integers.
2x+4(x+1)=2(x+2)+20
2x+4x+4=2x+4+20
6x+4=2x+24
6x-2x=24-4
4x=20
x=20/4
x=5 ans.
Proof:
2*5+4(5+1)=2(5+2)+20
10+4*6=2*7+20
10+24=14+20
34=34