SOLUTION: 2x^3+4x^2-18x-36=0

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Question 456209: 2x^3+4x^2-18x-36=0
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
2x^3+4x^2-18x-36=0
rearrange terms:
2x^3-18x+4x^2-36=0
group:
(2x^3-18x)+(4x^2-36)=0
factor each group:
2x(x^2-9)+4(x^2-9)=0
(x^2-9)(2x+4)=0
the term on left is a "difference of squares":
(x-3)(x+3)(2x+4)=0
x = {-3, 3, -2}