SOLUTION: i subscribe to the comic-of-the-month club. each month i can buy any number of the 48 titles offered by the club. the first month i bought five comic for $3.07. the second month i

Click here to see ALL problems on Miscellaneous Word Problems

Question 456188: i subscribe to the comic-of-the-month club. each month i can buy any number of the 48 titles offered by the club. the first month i bought five comic for $3.07. the second month i bought two comics for $1.72. the next month i bought six of the club offerings for $3.52. in may i bought three more for $2.17. the club charges a fee foe each comic and a handling fee for the entire order. how much would it have cost to buy all 48 titles at the same time?
i would like a step- by step explannTION AND IF I COULD GET AN ANSWER TODAY OR EARLY TOMORROW THAT WOULD BE GREAT THANKS.
Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
i subscribe to the comic-of-the-month club. each month i can buy any number of the 48 titles offered by the club.
the first month i bought five comic for $3.07.
the second month i bought two comics for $1.72.
the next month i bought six of the club offerings for $3.52.
in may i bought three more for $2.17.
the club charges a fee for each comic and a handling fee for the entire order.
how much would it have cost to buy all 48 titles at the same time?
:
Let c = cost of each comic
let f = fixed fee for each order
:
Write an equation for the first two months
5c + f = 3.07
2c + f = 1.72
----------------subtraction eliminates f, find c
3c = 1.35
c =
c = .45 for each comic
:
Find f using the 2nd month equation
2(.45) + f = 1.72
.90 + f = 1.72
f = 1.72 - .90
f = .82 fixed fee for each order
:
We could do the same with the last two months, but we got what we wanted
:
Buy all 48 titles in one order
48(.45) + .82 = $22.42