SOLUTION: Hi everyone, I have two problems to solve: x^2+3x-4=0 x^2+2x-8=0 Thank you, Gina

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Hi everyone, I have two problems to solve: x^2+3x-4=0 x^2+2x-8=0 Thank you, Gina      Log On


   

Question 456184: Hi everyone, I have two problems to solve:
x^2+3x-4=0
x^2+2x-8=0
Thank you,
Gina
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
Both can be solved by factoring.
x^2+3x-4=0
(x+4)(x-1) = 0
x = {-4, 1}
.
x^2+2x-8=0
(x+4)(x-2) = 0
x = {-4, 2}