SOLUTION: What is the period of the function y= (1/2)sin (x/3 - pie)
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Question 455924
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What is the period of the function y= (1/2)sin (x/3 - pie)
Answer by
stanbon(75887)
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What is the period of the function y= (1/2)sin (x/3 - pie)
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y = (1/2)sin[(1/3)x - pi)]
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Period = (2pi]/(1/3) = 6pi
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Cheers,
Stan H.
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