SOLUTION: Solve problem exactly ln (x + 1) = ln (3x + 1)- ln x
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Question 4558
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Solve problem exactly
ln (x + 1) = ln (3x + 1)- ln x
Answer by
rapaljer(4671)
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By the second law of logarithms,
Now, since there are ln s on both sides of the equation, raise both sides as a power of e:
Multiply both sides of this equation by x
Set equal to zero:
Solve by quadratic formula, where
and a= 1, b= -2, c = -1.
Factor the numerator, so you can reduce the fraction:
or
However, the second solution is a negative number, which is NOT allowed in the last ln expression. So the only solution is
R^2 at SCC