SOLUTION: Two numbers P and Q such that when divided by 6 ,they leave remainder 4 and 5 respectively.find remainder when (p square + Q square)divided by 6.

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Question 455451: Two numbers P and Q such that when divided by 6 ,they leave remainder 4 and 5 respectively.find remainder when (p square + Q square)divided by 6.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Two numbers P and Q such that when divided by 6 ,they leave remainder 4 and 5 respectively.
find remainder when %28p%5E2%2Bq%5E2%29%2F6
:
From the 1st sentence we can assume that Q = P+1
:
Assume that P = 10, then Q = 11
:
%2810%5E2+%2B+11%5E2%29%2F6 = %28100%2B121%29%2F6 221%2F6 = 36 remainder of 5
:
Try it with another pair of numbers, P=22, Q=23, remainder is 5