SOLUTION: a^2+b^2=c^2 (2x-2)^2+15^2=(2x+7)^2 4x^2+4+225=8x^2+18x 4+4+225=8+18x 233=8+18x 225=18x 12.5=x Did I solve this correctly? If not, what did I do wrong and how do I solve it

Algebra ->  Pythagorean-theorem -> SOLUTION: a^2+b^2=c^2 (2x-2)^2+15^2=(2x+7)^2 4x^2+4+225=8x^2+18x 4+4+225=8+18x 233=8+18x 225=18x 12.5=x Did I solve this correctly? If not, what did I do wrong and how do I solve it      Log On


   

Question 455301: a^2+b^2=c^2
(2x-2)^2+15^2=(2x+7)^2
4x^2+4+225=8x^2+18x
4+4+225=8+18x
233=8+18x
225=18x
12.5=x
Did I solve this correctly? If not, what did I do wrong and how do I solve it?
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
a^2+b^2=c^2
(2x-2)^2+15^2=(2x+7)^2
4x^2 - 8x + 4 + 225 = 4x^2 + 28x + 49
-8x + 229 = 28x + 49
-36x = -180
x = 5
----------
4x^2+4+225=8x^2+18x
4+4+225=8+18x
233=8+18x
225=18x
12.5=x

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
a^2+b^2=c^2
(2x-2)^2+15^2=(2x+7)^2
---
4x^2-8x+4 + 225 = 4x^2+28x+49
-----
-8x+229 = 28x+49
----
36x = 180
---
x = 5
=============
Cheers,
Stan H.