Question 455286: The ship Laughing Flower had already traveled 328 nautical miles at an average speed of 16 nautical miles per hour (knots) when The Floating bear left port to join in the race. If Laughing Flower continues at its current pace, how fast must The Floating bear travel in order to catch Laughing Flower by the end of the 1640-nautical mile race?
The Floating Bear must average _??_ knots in order to catch Laughing Flower by the end of the race
Answer by htmentor(1343)   (Show Source):
You can put this solution on YOUR website! The ship Laughing Flower had already traveled 328 nautical miles at an average speed of 16 nautical miles per hour (knots) when The Floating bear left port to join in the race. If Laughing Flower continues at its current pace, how fast must The Floating bear travel in order to catch Laughing Flower by the end of the 1640-nautical mile race?
The Floating Bear must average _??_ knots in order to catch Laughing Flower by the end of the race
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Let v = the speed of Floating Bear (FB)
If they meet at the end of the race, the race time for FB will be:
t = d/v = 1640/v
The time for Laughing Flower will be the same, but the distance is 1640-328=1312.
t = 1312/16
Set the times equal and solve for v:
1640/v = 1312/16
1312v = 1640*16
v = 20
So the speed of Laughing Flower is 20 knots
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