SOLUTION: Jane took 30 min to drive her boat upstream to water-ski at her favorite spot. Coming back later in the day, at the same boat speed, took her 1o min. If the current in that part of

Algebra ->  Expressions-with-variables -> SOLUTION: Jane took 30 min to drive her boat upstream to water-ski at her favorite spot. Coming back later in the day, at the same boat speed, took her 1o min. If the current in that part of      Log On


   



Question 455185: Jane took 30 min to drive her boat upstream to water-ski at her favorite spot. Coming back later in the day, at the same boat speed, took her 1o min. If the current in that part of the river is 3 km per hour, what was her boat speed in still water?
Can someone show me the set up for this?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Jane took 30 min to drive her boat upstream to water-ski at her favorite spot. Coming back later in the day, at the same boat speed, took her 1o min. If the current in that part of the river is 3 km per hour, what was her boat speed in still water?
Can someone show me the set up for this?
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Upstream DATA:
time = 1/2 hr ; distance = x km ; rate = d/t = x/(1/2) = (2x) km/h
-------------------
Downstream DATA:
time = 1/6 hr ; distance = x km ; rate = d/t = x/(1/6) = (6x) km/h
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Upstream rate = b-3 km/h where b is the speed of the boat in still water
Downstream rate b+3 km/h
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Solve this system of equations:
rate = rate:
b-3 = (2x)
b+3 = (6x)
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Subtract and solve for "x":
6 = 4x
----
x = 3/2 km
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Solve for "b":
b -3 = 2x
b -3 = 2(3/2)
b -3 = 3
b = 6 km/h (speed of the boat in still water)
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A shorter way to work the problem.
Let b+3 be downstream rate.
and b-3 be upstream rate.
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Distance up = Distance down = (rate)(time)
(b+3)(1/6 hr) = (b-3)(1/2 hr)
---
Multiply both sides by 12 to get:
2b+6 = 6b-18
4b = 24
b = 6 km/hr (speed of the boat in still water)
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Cheers,
Stan H.