Question 455141: a man shoots a rocket going 48 feet per second from a height 64 feet when will the rocket reach the ground and what is the max height? Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! a man shoots a rocket going 48 feet per second from a height 64 feet when will the rocket reach the ground and what is the max height?
h = -32t^2 + 42t + 64
reaches max at vertex
t value of vertex found by
t = -b/(2a)
t = -42/(2*(-32))
t = -42/(-64)
t = 21/32 seconds
t = .66 seconds
.
max height:
h = -32(.66)^2 + 42(.66) + 64
h = 77.8 feet
