SOLUTION: In a capture-recapture study, a biologist tagged and released 387 deer. A month later she captured 56 deer, 28 of which had tags. About how many deer were in the population?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: In a capture-recapture study, a biologist tagged and released 387 deer. A month later she captured 56 deer, 28 of which had tags. About how many deer were in the population?      Log On


   



Question 454935: In a capture-recapture study, a biologist tagged and released 387 deer. A month later she captured 56 deer, 28 of which had tags. About how many deer were in the population?
Found 3 solutions by jorel1380, edjones, csmarker:
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
13/47=274/n
13n=47x274
13n=12878
n=990.61 or about 991 deer..

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
x/47 = 274/13
x~991
.
Ed

Answer by csmarker(1) About Me  (Show Source):
You can put this solution on YOUR website!
28/56 = 387/n
Cross multiply:
28n = 387(56)
28n = 21,672
Divide each side by 28:
n=774