SOLUTION: The length of a rectangle is 4m longer than its width.
If the perimeter of the rectangle is 40m , find its area
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-> SOLUTION: The length of a rectangle is 4m longer than its width.
If the perimeter of the rectangle is 40m , find its area
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If the perimeter of the rectangle is 40m , find its area"
x = width
x + 4 = length {length is 4 longer than width}
Perimeter of a rectangle is 2(width) + 2(length.
2x + 2(x + 4) = 40 {perimeter is 2(width) + 2(length)}
2x + 2x + 8 = 40 {used distributive property}
4x + 8 = 40 {combined like terms}
4x = 32 {subtracted 8 from both sides}
x = 8 {divided both sides by 4}
x + 4 = 12 {substituted 8, in for x, into x + 4}
width = 8 and length = 12
Area of a rectangle is width x length
Area
= 8(12) {substituted 8 for width and 12 for length}
= 96 mē {multiplied} www.algebrahouse.com
