SOLUTION: A popular, nationwide standardized test taken by high-school juniors and seniors may or may not measure academic potential, but we can nonetheless attempt to predict performance in
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-> SOLUTION: A popular, nationwide standardized test taken by high-school juniors and seniors may or may not measure academic potential, but we can nonetheless attempt to predict performance in
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Question 454926: A popular, nationwide standardized test taken by high-school juniors and seniors may or may not measure academic potential, but we can nonetheless attempt to predict performance in college from performance on this test. We have chosen a random sample of fifteen students just finishing their first year of college, and for each student we've recorded her score on this standardized test (from 400 to 1600) and her grade point average (from 0 to 4) for her first year in college. The data are shown below, with x denoting the score on the standardized test and y denoting the first-year college grade point average. The least-squares regression line for these data is y-hat = 1.1372 + 0.0015x.
Standardized test score (x)
910
1350
1490
1300
1060
930
1490
1020
1240
1000
840
1110
1400
790
1200
Grade point average (y)
2.65
3.66
3.51
2.97
3.11
2.25
2.92
3.05
3.29
2.18
2.22
2.40
2.98
2.39
2.72
1. For these data, standardized test scores that are greater than the mean of the standardized test scores tend to be paired with grade point averages that are ------- the mean of the grade point average.
Greater than or Less than
I selected greater than
2. According to the regression equation for an increase of one point in standardized test score, there is a corresponding -------- of 0.0015 point in grade point average.
Increase or decrease
I selected increase
3. From the regression equation, what is the predicted grade point average when the standardized test score was 930? 2.53
4. What was the observed grade point average when the standardized test score was 930? 2.25
I would like to know if my answers are right or wrong. If wrong, show me the correct step to the correct answer. Thank you for your time.
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