SOLUTION: I'm not sure how to set up this problem. The number before the x in the exponent expression on the #3 confuses me. The problem is 3^2x=4^x I have set the problem up as 2xLog3=

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I'm not sure how to set up this problem. The number before the x in the exponent expression on the #3 confuses me. The problem is 3^2x=4^x I have set the problem up as 2xLog3=      Log On


   

Question 45492This question is from textbook
: I'm not sure how to set up this problem. The number before the x in the exponent expression on the #3 confuses me. The problem is 3^2x=4^x
I have set the problem up as 2xLog3=xlog4. The next step I believe is 2xLog3-xLog4=0, Factor out x. X(2log3-log4)=0. I don't know if this is right or what the next step would be. without the 2 in front of log 3 I would divide out the expression in the parenthesis to get x=0. Any help would be greatly appreciated thank you. Tamara This question is from textbook

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
3%5E%282x%29+=+4%5Ex
log%2810%2C3%5E%282x%29%29+=+log%2810%2C4%5Ex%29
2x%2Alog%2810%2C3%29+=+x%2Alog%2810%2C4%29
2%2Alog%2810%2C3%29+=+log%2810%2C4%29
log%2810%2C9%29+=+log%2810%2C4%29 No Solutions
Try A Different Approach:
3%5E%282x%29+=+4%5Ex
Anything but zero to the zero power is one.
x+=+0
+graph%28+600%2C+600%2C+-5%2C+0.5%2C+-0.5%2C+2%2C+3%5E%282x%29%2C+4%5Ex%29+