SOLUTION: Help me please! A cruise ship has a 74% chance of having leftover rooms the week before the cruise. There are 25 cruise ships setting sail this month. What is the mean and t

Algebra ->  Probability-and-statistics -> SOLUTION: Help me please! A cruise ship has a 74% chance of having leftover rooms the week before the cruise. There are 25 cruise ships setting sail this month. What is the mean and t      Log On


   



Question 454531: Help me please!
A cruise ship has a 74% chance of having leftover rooms the week before the cruise. There are 25 cruise ships setting sail this month.
What is the mean and the standard deviation for this approximation?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Help me please!
A cruise ship has a 74% chance of having leftover rooms the week before the cruise. There are 25 cruise ships setting sail this month.
What is the mean and the standard deviation for this approximation?
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mean = np = 25*0.74 = 18.5
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std = sqrt(npq) = sqrt(18.5*0.26] = 2.193..
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Cheers,
Stan H.