Question 454327: Solve the linear system by using substitution. 3x+2y=5, 5x-9y=-4
Found 3 solutions by mananth, ikleyn, josgarithmetic:
Answer by mananth(16949)   (Show Source):
You can put this solution on YOUR website! 3x+2y=5 .............1
9y=4+5x ---------2
/9 =
y=0.44+0.56x
Plug the value of y in (1)
3x+2(0.44+0.56x)
3x+0.89 +1.11x=5
3x+1.11 x=5-0.89
4.11x=4.11
/4.11
x=1
Plug the value of x in (1)
3x+2y=5
3*1+2y=5
3+2y=5
2y=2
/2
y=1
Answer by ikleyn(53570)  (Show Source):
You can put this solution on YOUR website! .
Solve the linear system by using substitution. 3x+2y=5, 5x-9y=-4
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In his post, @mananth makes 16 tons incorrect calculations.
A true solution, which I provide below, has nothing in common with the @mananth writing.
Your starting equations are
3x + 2y = 5, (1)
5x - 9y = -4. (2)
From equation (1), express y =  and substitute it into equation (2), replacing 'y' there
5x -  = -4.
Multiply both sides by 2 to rid of the numerator
10x - 9*((-3x)+5) = -8.
Simplify and find 'x' from this equation
10x + 27x - 45 = -8
37x = -8 + 45
37x = 37
x = 37/37 = 1.
Now substitute x = 1 into equation (1) and find 'y'
3*1 + 2y = 5 ---> 2y = 5 - 3 = 2 ---> y = 2/2 = 1.
ANSWER. x = 1, y = 1.
Solved.
Answer by josgarithmetic(39720)  (Show Source):
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