SOLUTION: Please help me solve this problem: 2^(3x+3)=2^(3x+1)+48 2^(3x)X 2^3-2^(3x)X 2=48 8^x X 8-8^x X 2=48

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Please help me solve this problem: 2^(3x+3)=2^(3x+1)+48 2^(3x)X 2^3-2^(3x)X 2=48 8^x X 8-8^x X 2=48       Log On


   

Question 454295: Please help me solve this problem: 2^(3x+3)=2^(3x+1)+48
2^(3x)X 2^3-2^(3x)X 2=48
8^x X 8-8^x X 2=48
Answer by Gogonati(855) About Me  (Show Source):
You can put this solution on YOUR website!
We rewrite the equation in the form:2%5E2%2A2%5E%283x%2B1%29-2%5E%283x%2B1%29=48, substituting
2%5E%283x%2B1%29=y we get the linear equation:4y-y=48, where y=16.
Now we easy can find the values of x from our substitution: 2%5E%283x%2B1%29=16=>
=>2%5E%283x%2B1%29=2%5E4=>3x%2B1=4=>x=1.