SOLUTION: find the domain of f(x)=(sqrt(x-5))/(x^2-3x-10)

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Question 454262: find the domain of f(x)=(sqrt(x-5))/(x^2-3x-10)
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
The domain of sqrt%28x-5%29 is x-5+%3E=0, or x+%3E=+5.
The domain of 1%2F%28x%5E2+-+3x+-+10%29+=+1%2F%28%28x-5%29%28x%2B2%29%29 is all real numbers except 5 and -2.
Intersect these two domains, excluding all x-values that make the denominator equal to zero.
Hence the domain is x > 5.