SOLUTION: Find the specific standard equation for: 4y^2-x^2-16y-2x+3=0

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Question 454200: Find the specific standard equation for:
4y^2-x^2-16y-2x+3=0
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the specific standard equation for:
4y^2-x^2-16y-2x+3=0
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4y^2-x^2-16y-2x+3=0
completing the square
4(y^2-4y+4)-(x^2+2x+1)=-3+16-1=12
4(y-2)^2-(x+1)^2=12
Equation of conic:
(y-2)^2/3-(x+1)^2/12=1
This is a hyperbola with vertical transverse axis and center at (-1, 2)
See graph below as a visual check on the equation
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y=(3+(x+1)^2/4)^.5+2