SOLUTION: a private learjet 31a was flying with a tailwind and travel 1120 mi in 2 h. flying against the wind on the return trip, the jet was able to travel only 980 mi in 2 h. find the spee

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Question 453870: a private learjet 31a was flying with a tailwind and travel 1120 mi in 2 h. flying against the wind on the return trip, the jet was able to travel only 980 mi in 2 h. find the speed of the jet in calm air and the rate of the wind

Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
1120/2=560
980/2=490
560+490/2=1050/2=525 mph average speed of plane in still air
560-525=35
525-490=35
Wind speed is 35 mph..