SOLUTION: 3+4(6-2) to my mind its 3+4=7*6-2=28 my son thinks the answer in 5. i cant see it, can someone explain this please also, insert the pair of brackets on order to make this calc

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Question 453867: 3+4(6-2)
to my mind its 3+4=7*6-2=28
my son thinks the answer in 5.
i cant see it, can someone explain this please
also,
insert the pair of brackets on order to make this calculation work
8-4+6/2=1
again,the closest i can get to is -1 which is no help,
thank you in advance,
phil

Found 3 solutions by rwm, prmarella, MathTherapy:
Answer by rwm(914)   (Show Source):
You can put this solution on YOUR website!
Where are the fractions ?
how does your son get 5?
it is 19
6-2=4
4*4=16
16+3=19
and
8-(4+6/2)=1
8-7=1
how did you get -1?

Answer by prmarella(4)   (Show Source):
You can put this solution on YOUR website!
The problem is 3+4(6-2)
According to BODMAS rule we should simplify in the order of Brackets ,OF, Division, Multiplication ,Addition and finally Subtraction .
Accordingly in the above problem we should first simplify the Bracket then multiplication and then only addition.
So we first take up the numbers in the brackets that is (6-2)=4
Accordingly the problem becomes
3+4(6-2) =3+4(4) = 3+16 =19
Hence 19 is the correct answer.
If we add 3 and 4 first, we get wrong result.
Thank you very much for giving me the opportunity to explain
prabhakara rao

Answer by MathTherapy(10552)   (Show Source):
You can put this solution on YOUR website!
3+4(6-2)
to my mind its 3+4=7*6-2=28
my son thinks the answer in 5.
i cant see it, can someone explain this please
also,
insert the pair of brackets on order to make this calculation work
8-4+6/2=1
again,the closest i can get to is -1 which is no help,
thank you in advance,
phil

Neither is correct!!
3 + 4(6 � 2)
3 + 4(4)
3 + 16 ------- Applying PEMDAS, in which multiplication is done before addition

8 � (4 + 3) = 1