You can put this solution on YOUR website! how do you graph y^2-x^2=9
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Standard form of a hyperbola with horizontal transverse axis: (x-h)^2/a^2-(y-k)^2/b^2=1, with (h,k) being the (x,y) coordinates of the center.
Standard form of a hyperbola with vertical transverse axis: (y-k)^2/a^2-(x-h)^2/b^2=1, with (h,k) being the (x,y) coordinates of the center.
The difference between the two forms is the interchange of (x-h) and (y-k)
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y^2-x^2=9
y^2/9-x^2/9=1
Given equation is a hyperbola with center at (0, 0) and it has a vertical transverse axis.
a^2=9
a=3
2a=6=transverse axis
vertices: (0,0±3)
b^2=9
b=3
2b=6=conjugate axis
Equation of asymptotes: y=±(a/b)x
See the graph below as a visual check
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y=(9+x^2)^.5
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