SOLUTION: solve by completing the square. x^2+4x-12=0
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Question 453794
:
solve by completing the square.
x^2+4x-12=0
Found 2 solutions by
mananth, Alan3354
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Answer by
mananth(16946)
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x^2+4x-12=0
x^2+4x=12
x^2+4x+4=12+4
(x+2)^2=16
take the square root
x+2=4
x=2
Answer by
Alan3354(69443)
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x^2+4x-12=0
x^2+4x = 12
x^2+4x+4 = 12+4
(x+2)^2=16
x+2= +/-4
x = -6, 2