Question 453755: Hello, I am a completely stumped as to how to solve this problem! I've been working on it for two days and can't seem to figure out the correct set-up. Any help would be greatly appreciated. Thank you.
The Fancy Fashions Store had $8000 available each month for advertising. Newspaper ads cost $400 each and no more than 20 can be run per month. Radio ads cost $200 each and no more than 30 can run per month. TV ads cost $1200 each, with a maximum of 6 available each month. Approximately 2000 women will see each newspaper ad, 1200 will hear each radio commercial, and 10,000 will see each TV ad.
a. How much of each type of advertising should be used if the store wants to maximize its ad exposure?
b. A marketing analyst is puzzled by the results of part a. More women see each newspaper ad than hear each radio commercial, he reasons, so it makes no sense to use radio commercials and no newspaper ads. How would you respond?
Answer by edjones(8007)   (Show Source):
You can put this solution on YOUR website! The cost of tv/viewer is 1200/10000=$0.12
For radio it is 200/1200=$0.17
For newspaper it is 400/2000=$0.20
.
Do 6 TV ads $7200 and 4 radio ads $800.
6*10000+4*1200=64,800 exposures.
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Ed
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