Question 45364: Suppose that you randomly select a two digit number (that is one of 00,01,01,...99) from a sequence of random numbers obtained by repeatedly spinning a spinner. What is the probability that the number selected is less than 10? That the number selected is even or is less than 50. and that the number selected is even given that it is less than 50?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Suppose that you randomly select a two digit number (that is one of 00,01,01,...99) from a sequence of random numbers obtained by repeatedly spinning a spinner.
What is the probability that the number selected is less than 10?
00 to 09 is ten numbers.
00 to 99 is 100 numbers.
P(numbers less than 10)=10/100 = 0.1
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That the number selected is even or is less than 50.
Prob(even or <50)=Prob(even)+Prob(<50)-Prob(even and<50)
=50/100 + 50/100 - 25/100 = 75/100
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The number selected is even given that it is less than 50?
Prob(even given <50) = [prob(even and <50)]/[Prob(<50)]
[25/100]/[50/100)= 1/2
Cheers,
Stan H.
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