SOLUTION: Question 3 Find the mean, variance, and standard deviation of the binomial distribution with the given values of n and p. n = 90 p = .6 mean of a binomial distribution =

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Question 453594: Question 3
Find the mean, variance, and standard deviation of the binomial distribution with the given values of n and p. n = 90 p = .6
mean of a binomial distribution = np 90 * .6 = 54
q = 1-p 1- .6 = .4
variance = npq 54 * .4 = 21.6
Standard Deviation = sqrt(npq) = ( my answer does not come out correctly when I get to this part)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You should have gotten


Standard Deviation = sqrt%28npq%29+=+sqrt%2890%2A.6%2A.4%29+=+4.6475800154489