SOLUTION: In the triangle KLM the length of KM is approximately what?: (Round to the nearest tenth)
KL= 7in
Angle M= 110 degrees
Angle L=30 degrees
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-> SOLUTION: In the triangle KLM the length of KM is approximately what?: (Round to the nearest tenth)
KL= 7in
Angle M= 110 degrees
Angle L=30 degrees
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Question 453477: In the triangle KLM the length of KM is approximately what?: (Round to the nearest tenth)
KL= 7in
Angle M= 110 degrees
Angle L=30 degrees Answer by pedjajov(51) (Show Source):
You can put this solution on YOUR website! If we draw a height (h) from vertex M it forms two right triangles LNM and KNM where N is a point where height h intersects KL.
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It also divides KL into two pieces x=KN and y=LN: -> x=7-y
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Knowing that angle L=30 and angle M=110, it makes angle K=40.
Now we have: -> h=tan(30)*y -> h=tan(40)*x
: , substitute x with 7-y
y=4.1
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x=7-y -> x=7-4.1 -> x=2.9
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We can find KM knowing that:
KM=3.8