SOLUTION: solve this plzz: sin^2xcosx-1=0 & cos2x-3sinx=2

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Question 453421: solve this plzz:
sin^2xcosx-1=0
&
cos2x-3sinx=2

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
sin^2x * cosx - 1 = 0
---
(1-cos^2)(cos) = 1
---
-cos^3+cos-1 = 0
cos^3-cos+1 = 0
----
That doesn't lead to anything interesting.
Are you sure you posted the problem
correctly?



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cos(2x)-3sinx = 2
---
1-2sin^2 -3sin = 2
---
2sin^2+3sin+1 = 0
Factor:
(2sin+1)(sin+1) = 0
---
sin(x) = -1/2 or sin(x) = -1
---
x = 330 degrees or 210 degrees or 270 degrees
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Cheers,
Stan H.
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